Impara online a risolvere i problemi di passo dopo passo. d/dx(((x^2+1)/(x^2-1))^(1/9)). Applicare la formula: \frac{d}{dx}\left(x^a\right)=ax^{\left(a-1\right)}\frac{d}{dx}\left(x\right), dove a=\frac{1}{9} e x=\frac{x^2+1}{x^2-1}. Applicare la formula: \left(\frac{a}{b}\right)^n=\left(\frac{b}{a}\right)^{\left|n\right|}, dove a=x^2+1, b=x^2-1 e n=-\frac{8}{9}. Applicare la formula: \frac{d}{dx}\left(\frac{a}{b}\right)=\frac{\frac{d}{dx}\left(a\right)b-a\frac{d}{dx}\left(b\right)}{b^2}, dove a=x^2+1 e b=x^2-1. Applicare la formula: \frac{a}{b}\frac{c}{f}=\frac{ac}{bf}, dove a=1, b=9, c=\frac{d}{dx}\left(x^2+1\right)\left(x^2-1\right)-\left(x^2+1\right)\frac{d}{dx}\left(x^2-1\right), a/b=\frac{1}{9}, f=\left(x^2-1\right)^2, c/f=\frac{\frac{d}{dx}\left(x^2+1\right)\left(x^2-1\right)-\left(x^2+1\right)\frac{d}{dx}\left(x^2-1\right)}{\left(x^2-1\right)^2} e a/bc/f=\frac{1}{9}\sqrt[9]{\left(\frac{x^2-1}{x^2+1}\right)^{8}}\frac{\frac{d}{dx}\left(x^2+1\right)\left(x^2-1\right)-\left(x^2+1\right)\frac{d}{dx}\left(x^2-1\right)}{\left(x^2-1\right)^2}.

d/dx(((x^2+1)/(x^2-1))^(1/9))