Impara online a risolvere i problemi di passo dopo passo. dx/dycos(3y)^2+sin(3y)^2=y+7. Applicare la formula: a\frac{dy}{dx}+c=f\to \frac{dy}{dx}+\frac{c}{a}=\frac{f}{a}, dove a=\cos\left(3y\right)^2, c=\sin\left(3y\right)^2 e f=y+7. Applicare l'identità trigonometrica: \frac{\sin\left(\theta \right)^n}{\cos\left(\theta \right)^n}=\tan\left(\theta \right)^n, dove x=3y e n=2. Applicare la formula: x+a=b\to x=b-a, dove a=\tan\left(3y\right)^2, b=\frac{y+7}{\cos\left(3y\right)^2}, x+a=b=\frac{dx}{dy}+\tan\left(3y\right)^2=\frac{y+7}{\cos\left(3y\right)^2}, x=\frac{dx}{dy} e x+a=\frac{dx}{dy}+\tan\left(3y\right)^2. Applicare la formula: \frac{x}{a}=b\to x=ba, dove a=dy, b=\frac{y+7}{\cos\left(3y\right)^2}-\tan\left(3y\right)^2 e x=dx.

dx/dycos(3y)^2+sin(3y)^2=y+7