$\frac{dy}{dx}=xy-1$

Step-by-step Solution

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Final answer to the problem

$y=\left(-\sum_{n=0}^{\infty } \frac{{\left(\left(-\frac{1}{2}\right)\right)}^nx^{\left(2n+1\right)}}{\left(2n+1\right)\left(n!\right)}+C_0\right)e^{\frac{1}{2}x^2}$
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Step-by-step Solution

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1

Rearrange the differential equation

$\frac{dy}{dx}-xy=-1$

Learn how to solve equazioni differenziali problems step by step online.

$\frac{dy}{dx}-xy=-1$

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Learn how to solve equazioni differenziali problems step by step online. dy/dx=xy-1. Rearrange the differential equation. We can identify that the differential equation has the form: \frac{dy}{dx} + P(x)\cdot y(x) = Q(x), so we can classify it as a linear first order differential equation, where P(x)=-x and Q(x)=-1. In order to solve the differential equation, the first step is to find the integrating factor \mu(x). To find \mu(x), we first need to calculate \int P(x)dx. So the integrating factor \mu(x) is.

Final answer to the problem

$y=\left(-\sum_{n=0}^{\infty } \frac{{\left(\left(-\frac{1}{2}\right)\right)}^nx^{\left(2n+1\right)}}{\left(2n+1\right)\left(n!\right)}+C_0\right)e^{\frac{1}{2}x^2}$

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Function Plot

Plotting: $\frac{dy}{dx}-xy+1$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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