Impara online a risolvere i problemi di divisione lunga polinomiale passo dopo passo. Solve the inequality (n+1)/(2^(n+3))<=n/(2^(n+2)). Applicare la formula: \frac{a}{b}\leq c=a\leq cb, dove a=n+1, b=2^{\left(n+3\right)} e c=\frac{n}{2^{\left(n+2\right)}}. Applicare la formula: a\frac{b}{c}=\frac{ba}{c}, dove a=2^{\left(n+3\right)}, b=n e c=2^{\left(n+2\right)}. Applicare la formula: \frac{a^m}{a^n}=a^{\left(m-n\right)}, dove a^n=2^{\left(n+2\right)}, a^m=2^{\left(n+3\right)}, a=2, a^m/a^n=\frac{n2^{\left(n+3\right)}}{2^{\left(n+2\right)}}, m=n+3 e n=n+2. Applicare la formula: -\left(a+b\right)=-a-b, dove a=n, b=2, -1.0=-1 e a+b=n+2.

Solve the inequality (n+1)/(2^(n+3))<=n/(2^(n+2))