Esercizio
$\frac{x^{4}+3x^{3}+2x^{2}+5x+4}{x+2}$
Soluzione passo-passo
1
Dividere $x^4+3x^3+2x^2+5x+4$ per $x+2$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+2;}{\phantom{;}x^{3}+x^{2}\phantom{-;x^n}+5\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+2\overline{\smash{)}\phantom{;}x^{4}+3x^{3}+2x^{2}+5x\phantom{;}+4\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+2;}\underline{-x^{4}-2x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-x^{4}-2x^{3};}\phantom{;}x^{3}+2x^{2}+5x\phantom{;}+4\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+2-;x^n;}\underline{-x^{3}-2x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;-x^{3}-2x^{2}-;x^n;}\phantom{;}5x\phantom{;}+4\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+2-;x^n-;x^n;}\underline{-5x\phantom{;}-10\phantom{;}\phantom{;}}\\\phantom{;;-5x\phantom{;}-10\phantom{;}\phantom{;}-;x^n-;x^n;}-6\phantom{;}\phantom{;}\\\end{array}$
$x^{3}+x^{2}+5+\frac{-6}{x+2}$
Risposta finale al problema
$x^{3}+x^{2}+5+\frac{-6}{x+2}$