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$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$

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Solution

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Final answer to the problem

$y=\sqrt{\frac{b^2\left(a^2-x^2\right)}{a^2}},\:y=-\sqrt{\frac{b^2\left(a^2-x^2\right)}{a^2}}$
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The least common multiple (LCM) of a sum of algebraic fractions consists of the product of the common factors with the greatest exponent, and the uncommon factors

$L.C.M.=a^2b^2$

Learn how to solve equazioni differenziali problems step by step online.

$L.C.M.=a^2b^2$

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Learn how to solve equazioni differenziali problems step by step online. (x^2)/(a^2)+(y^2)/(b^2)=1. The least common multiple (LCM) of a sum of algebraic fractions consists of the product of the common factors with the greatest exponent, and the uncommon factors. Obtained the least common multiple (LCM), we place it as the denominator of each fraction, and in the numerator of each fraction we add the factors that we need to complete. Combine and simplify all terms in the same fraction with common denominator a^2b^2. Apply the formula: \frac{a}{b}=c\to a=cb, where a=x^2b^2+y^2a^2, b=a^2b^2 and c=1.

Final answer to the problem

$y=\sqrt{\frac{b^2\left(a^2-x^2\right)}{a^2}},\:y=-\sqrt{\frac{b^2\left(a^2-x^2\right)}{a^2}}$

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Plotting: $\frac{x^2}{a^2}+\frac{y^2}{b^2}-1$

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a
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n
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x
y
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.
(◻)
+
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×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Equazioni differenziali

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