Esercizio
$\frac{x^2-12x+40}{x-5}$
Soluzione passo-passo
1
Dividere $x^2-12x+40$ per $x-5$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-5;}{\phantom{;}x\phantom{;}-7\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-5\overline{\smash{)}\phantom{;}x^{2}-12x\phantom{;}+40\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-5;}\underline{-x^{2}+5x\phantom{;}\phantom{-;x^n}}\\\phantom{-x^{2}+5x\phantom{;};}-7x\phantom{;}+40\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-5-;x^n;}\underline{\phantom{;}7x\phantom{;}-35\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}7x\phantom{;}-35\phantom{;}\phantom{;}-;x^n;}\phantom{;}5\phantom{;}\phantom{;}\\\end{array}$
Risposta finale al problema
$x-7+\frac{5}{x-5}$