Esercizio
$\frac{x^3+3x^2-9x-18}{x^2-9}$
Soluzione passo-passo
1
Dividere $x^3+3x^2-9x-18$ per $x^2-9$
$\begin{array}{l}\phantom{\phantom{;}x^{2}-9;}{\phantom{;}x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{;}x^{2}-9\overline{\smash{)}\phantom{;}x^{3}+3x^{2}-9x\phantom{;}-18\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}-9;}\underline{-x^{3}\phantom{-;x^n}+9x\phantom{;}\phantom{-;x^n}}\\\phantom{-x^{3}+9x\phantom{;};}\phantom{;}3x^{2}\phantom{-;x^n}-18\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-9-;x^n;}\underline{-3x^{2}\phantom{-;x^n}+27\phantom{;}\phantom{;}}\\\phantom{;-3x^{2}+27\phantom{;}\phantom{;}-;x^n;}\phantom{;}9\phantom{;}\phantom{;}\\\end{array}$
$x+3+\frac{9}{x^2-9}$
Risposta finale al problema
$x+3+\frac{9}{x^2-9}$