Esercizio
$\frac{x^3-8x^2+17x-10}{x-3}$
Soluzione passo-passo
1
Dividere $x^3-8x^2+17x-10$ per $x-3$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-3;}{\phantom{;}x^{2}-5x\phantom{;}+2\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-3\overline{\smash{)}\phantom{;}x^{3}-8x^{2}+17x\phantom{;}-10\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-3;}\underline{-x^{3}+3x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-x^{3}+3x^{2};}-5x^{2}+17x\phantom{;}-10\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-3-;x^n;}\underline{\phantom{;}5x^{2}-15x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}5x^{2}-15x\phantom{;}-;x^n;}\phantom{;}2x\phantom{;}-10\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-3-;x^n-;x^n;}\underline{-2x\phantom{;}+6\phantom{;}\phantom{;}}\\\phantom{;;-2x\phantom{;}+6\phantom{;}\phantom{;}-;x^n-;x^n;}-4\phantom{;}\phantom{;}\\\end{array}$
$x^{2}-5x+2+\frac{-4}{x-3}$
Risposta finale al problema
$x^{2}-5x+2+\frac{-4}{x-3}$