Esercizio
$\frac{x^4+x^3+x^2-3x+2}{x-2}$
Soluzione passo-passo
1
Dividere $x^4+x^3+x^2-3x+2$ per $x-2$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-2;}{\phantom{;}x^{3}+3x^{2}+7x\phantom{;}+11\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-2\overline{\smash{)}\phantom{;}x^{4}+x^{3}+x^{2}-3x\phantom{;}+2\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-2;}\underline{-x^{4}+2x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-x^{4}+2x^{3};}\phantom{;}3x^{3}+x^{2}-3x\phantom{;}+2\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-2-;x^n;}\underline{-3x^{3}+6x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;-3x^{3}+6x^{2}-;x^n;}\phantom{;}7x^{2}-3x\phantom{;}+2\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-2-;x^n-;x^n;}\underline{-7x^{2}+14x\phantom{;}\phantom{-;x^n}}\\\phantom{;;-7x^{2}+14x\phantom{;}-;x^n-;x^n;}\phantom{;}11x\phantom{;}+2\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-2-;x^n-;x^n-;x^n;}\underline{-11x\phantom{;}+22\phantom{;}\phantom{;}}\\\phantom{;;;-11x\phantom{;}+22\phantom{;}\phantom{;}-;x^n-;x^n-;x^n;}\phantom{;}24\phantom{;}\phantom{;}\\\end{array}$
$x^{3}+3x^{2}+7x+11+\frac{24}{x-2}$
Risposta finale al problema
$x^{3}+3x^{2}+7x+11+\frac{24}{x-2}$