Esercizio
$\frac{x^4-2x^2+2x-35}{x+3}$
Soluzione passo-passo
1
Dividere $x^4-2x^2+2x-35$ per $x+3$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+3;}{\phantom{;}x^{3}-3x^{2}+7x\phantom{;}-19\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+3\overline{\smash{)}\phantom{;}x^{4}\phantom{-;x^n}-2x^{2}+2x\phantom{;}-35\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+3;}\underline{-x^{4}-3x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-x^{4}-3x^{3};}-3x^{3}-2x^{2}+2x\phantom{;}-35\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+3-;x^n;}\underline{\phantom{;}3x^{3}+9x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;\phantom{;}3x^{3}+9x^{2}-;x^n;}\phantom{;}7x^{2}+2x\phantom{;}-35\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+3-;x^n-;x^n;}\underline{-7x^{2}-21x\phantom{;}\phantom{-;x^n}}\\\phantom{;;-7x^{2}-21x\phantom{;}-;x^n-;x^n;}-19x\phantom{;}-35\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+3-;x^n-;x^n-;x^n;}\underline{\phantom{;}19x\phantom{;}+57\phantom{;}\phantom{;}}\\\phantom{;;;\phantom{;}19x\phantom{;}+57\phantom{;}\phantom{;}-;x^n-;x^n-;x^n;}\phantom{;}22\phantom{;}\phantom{;}\\\end{array}$
$x^{3}-3x^{2}+7x-19+\frac{22}{x+3}$
Risposta finale al problema
$x^{3}-3x^{2}+7x-19+\frac{22}{x+3}$