Esercizio
$\frac{x^4-3x^3+2x^2-x+8}{x-1}$
Soluzione passo-passo
1
Dividere $x^4-3x^3+2x^2-x+8$ per $x-1$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-1;}{\phantom{;}x^{3}-2x^{2}\phantom{-;x^n}-1\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-1\overline{\smash{)}\phantom{;}x^{4}-3x^{3}+2x^{2}-x\phantom{;}+8\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-1;}\underline{-x^{4}+x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-x^{4}+x^{3};}-2x^{3}+2x^{2}-x\phantom{;}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-1-;x^n;}\underline{\phantom{;}2x^{3}-2x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;\phantom{;}2x^{3}-2x^{2}-;x^n;}-x\phantom{;}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-1-;x^n-;x^n;}\underline{\phantom{;}x\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{;;\phantom{;}x\phantom{;}-1\phantom{;}\phantom{;}-;x^n-;x^n;}\phantom{;}7\phantom{;}\phantom{;}\\\end{array}$
$x^{3}-2x^{2}-1+\frac{7}{x-1}$
Risposta finale al problema
$x^{3}-2x^{2}-1+\frac{7}{x-1}$