Esercizio
$\frac{x^4-9x^2+4}{x^2-3}$
Soluzione passo-passo
1
Dividere $x^4-9x^2+4$ per $x^2-3$
$\begin{array}{l}\phantom{\phantom{;}x^{2}-3;}{\phantom{;}x^{2}\phantom{-;x^n}-6\phantom{;}\phantom{;}}\\\phantom{;}x^{2}-3\overline{\smash{)}\phantom{;}x^{4}\phantom{-;x^n}-9x^{2}\phantom{-;x^n}+4\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}-3;}\underline{-x^{4}\phantom{-;x^n}+3x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-x^{4}+3x^{2};}-6x^{2}\phantom{-;x^n}+4\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-3-;x^n;}\underline{\phantom{;}6x^{2}\phantom{-;x^n}-18\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}6x^{2}-18\phantom{;}\phantom{;}-;x^n;}-14\phantom{;}\phantom{;}\\\end{array}$
$x^{2}-6+\frac{-14}{x^2-3}$
Risposta finale al problema
$x^{2}-6+\frac{-14}{x^2-3}$