Esercizio
$\frac{x^5}{4x^2+1}$
Soluzione passo-passo
1
Dividere $x^5$ per $4x^2+1$
$\begin{array}{l}\phantom{\phantom{;}4x^{2}+1;}{\frac{1}{4}x^{3}\phantom{-;x^n}+\frac{-\frac{1}{4}}{4}x\phantom{;}\phantom{-;x^n}}\\\phantom{;}4x^{2}+1\overline{\smash{)}\phantom{;}x^{5}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{\phantom{;}4x^{2}+1;}\underline{-x^{5}\phantom{-;x^n}-\frac{1}{4}x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-x^{5}-\frac{1}{4}x^{3};}-\frac{1}{4}x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}\\\phantom{\phantom{;}4x^{2}+1-;x^n;}\underline{\phantom{;}0.25x^{3}\phantom{-;x^n}+\frac{1}{16}x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}0.25x^{3}+\frac{1}{16}x\phantom{;}-;x^n;}\frac{1}{16}x\phantom{;}\phantom{-;x^n}\\\end{array}$
$\frac{1}{4}x^{3}-\frac{1}{16}x+\frac{\frac{1}{16}x}{4x^2+1}$
Risposta finale al problema
$\frac{1}{4}x^{3}-\frac{1}{16}x+\frac{\frac{1}{16}x}{4x^2+1}$