Applicare la formula: $\frac{b^na^n}{c}$$=\frac{expand\left(ab\right)^n}{c}$, dove $a^n=\left(x-6\right)^7$, $a=x$, $b=x-6$, $b^n=x^7$, $c=\left(x^2+3\right)^6$, $b^na^n=x^7\left(x-6\right)^7$, $b^na^n/c=\frac{x^7\left(x-6\right)^7}{\left(x^2+3\right)^6}$ e $n=7$