$\int\frac{1}{x^2-6x+13}dx$

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Final answer to the problem

$\frac{\arctan\left(\frac{x}{\sqrt{13-6x}}\right)}{\sqrt{13-6x}}+C_0$
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Apply the formula: $\int\frac{n}{x^2+b}dx$$=\frac{n}{\sqrt{b}}\arctan\left(\frac{x}{\sqrt{b}}\right)+C$, where $b=13-6x$ and $n=1$

$\frac{1}{\sqrt{13-6x}}\arctan\left(\frac{x}{\sqrt{13-6x}}\right)$

Learn how to solve integrali di funzioni razionali problems step by step online.

$\frac{1}{\sqrt{13-6x}}\arctan\left(\frac{x}{\sqrt{13-6x}}\right)$

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Learn how to solve integrali di funzioni razionali problems step by step online. int(1/(x^2-6x+13))dx. Apply the formula: \int\frac{n}{x^2+b}dx=\frac{n}{\sqrt{b}}\arctan\left(\frac{x}{\sqrt{b}}\right)+C, where b=13-6x and n=1. Apply the formula: a\frac{b}{x}=\frac{ab}{x}. As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration C.

Final answer to the problem

$\frac{\arctan\left(\frac{x}{\sqrt{13-6x}}\right)}{\sqrt{13-6x}}+C_0$

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Plotting: $\frac{\arctan\left(\frac{x}{\sqrt{13-6x}}\right)}{\sqrt{13-6x}}+C_0$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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