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Rewrite the expression $\frac{6x}{x^3-8}$ inside the integral in factored form
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$\int\frac{6x}{\left(x-2\right)\left(x^2+2x+4\right)}dx$
Learn how to solve problems step by step online. int((6x)/(x^3-8))dx. Rewrite the expression \frac{6x}{x^3-8} inside the integral in factored form. Apply the formula: \int\frac{ab}{c}dx=a\int\frac{b}{c}dx, where a=6, b=x and c=\left(x-2\right)\left(x^2+2x+4\right). Rewrite the fraction \frac{x}{\left(x-2\right)\left(x^2+2x+4\right)} in 2 simpler fractions using partial fraction decomposition. Expand the integral \int\left(\frac{1}{6\left(x-2\right)}+\frac{-\frac{1}{6}x+\frac{1}{3}}{x^2+2x+4}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately.