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Apply the formula: $\int\ln\left(x+b\right)dx$$=\left(x+b\right)\ln\left(x+b\right)-\left(x+b\right)+C$, where $b=2$, $x=x^2$ and $x+b=x^2+2$
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$\left(x^2+2\right)\ln\left|x^2+2\right|-\left(x^2+2\right)$
Learn how to solve problems step by step online. int(ln(x^2+2))dx. Apply the formula: \int\ln\left(x+b\right)dx=\left(x+b\right)\ln\left(x+b\right)-\left(x+b\right)+C, where b=2, x=x^2 and x+b=x^2+2. Apply the formula: -\left(a+b\right)=-a-b, where a=x^2, b=2, -1.0=-1 and a+b=x^2+2. As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration C. We can combine and rename -2 and C_0 as other constant of integration.
