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Apply the formula: $\int\arctan\left(\theta \right)dx$$=var\arctan\left(\theta \right)-\int\frac{\theta }{1+\theta ^2}dx$, where $a=x$
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$x\arctan\left(x\right)-\int\frac{x}{1+x^2}dx$
Learn how to solve integrali trigonometrici problems step by step online. int(arctan(x))dx. Apply the formula: \int\arctan\left(\theta \right)dx=var\arctan\left(\theta \right)-\int\frac{\theta }{1+\theta ^2}dx, where a=x. The integral -\int\frac{x}{1+x^2}dx results in: -\frac{1}{2}\ln\left(1+x^2\right). Gather the results of all integrals. As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration C.
