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Apply the formula: $\int\ln\left(x+b\right)dx$$=\left(x+b\right)\ln\left(x+b\right)-\left(x+b\right)+C$, where $b=1$ and $x+b=1+x$
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$\left[\left(\left(x+1\right)\ln\left|x+1\right|-\left(x+1\right)\right)\right]_{0}^{1}$
Learn how to solve integrali definiti problems step by step online. int(ln(1+x))dx&0&1. Apply the formula: \int\ln\left(x+b\right)dx=\left(x+b\right)\ln\left(x+b\right)-\left(x+b\right)+C, where b=1 and x+b=1+x. Apply the formula: -\left(a+b\right)=-a-b, where a=x, b=1, -1.0=-1 and a+b=x+1. Apply the formula: \left[x\right]_{a}^{b}=eval\left(x,b\right)-eval\left(x,a\right)+C, where a=0, b=1 and x=\left(x+1\right)\ln\left(x+1\right)-x-1.
