Simplify $\left(\cos\left(x\right)^5\right)^{\frac{x}{\sin\left(2x\right)-\tan\left(2x\right)}}$ using the power of a power property: $\left(a^m\right)^n=a^{m\cdot n}$. In the expression, $m$ equals $5$ and $n$ equals $\frac{x}{\sin\left(2x\right)-\tan\left(2x\right)}$

Applicare la formula: $a\frac{b}{c}$$=\frac{ba}{c}$, dove $a=5$, $b=x$ e $c=\sin\left(2x\right)-\tan\left(2x\right)$