Esercizio
$\left(\cos b+\sin b\right)^2=1+x$
Soluzione passo-passo
Impara online a risolvere i problemi di passo dopo passo. Solve the equation (cos(b)+sin(b))^2=1+x. Applicare la formula: x^a=b\to \left(x^a\right)^{\frac{1}{a}}=\pm b^{\frac{1}{a}}, dove a=2, b=1+x e x=\cos\left(b\right)+\sin\left(b\right). Applicare la formula: \left(x^a\right)^b=x, dove a=2, b=1, x^a^b=\sqrt{\left(\cos\left(b\right)+\sin\left(b\right)\right)^2}, x=\cos\left(b\right)+\sin\left(b\right) e x^a=\left(\cos\left(b\right)+\sin\left(b\right)\right)^2. Applicare la formula: x+a=b\to x=b-a, dove a=\sin\left(b\right), b=\pm \sqrt{1+x}, x+a=b=\cos\left(b\right)+\sin\left(b\right)=\pm \sqrt{1+x}, x=\cos\left(b\right) e x+a=\cos\left(b\right)+\sin\left(b\right). Applicare la formula: a=c\pm b\to a=c+b,\:a=c-b, dove a=\cos\left(b\right), b=\sqrt{1+x} e c=-\sin\left(b\right).
Solve the equation (cos(b)+sin(b))^2=1+x
Risposta finale al problema
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