Esercizio
$\left(\frac{a^2}{9}+\frac{b^2}{2}\right)\cdot\left(\frac{a}{3}-\frac{b^2}{2}\right)$
Soluzione passo-passo
Impara online a risolvere i problemi di passo dopo passo. ((a^2)/9+(b^2)/2)(a/3+(-b^2)/2). Applicare la formula: x\left(a+b\right)=xa+xb, dove a=\frac{a^2}{9}, b=\frac{b^2}{2}, x=\frac{a}{3}+\frac{-b^2}{2} e a+b=\frac{a^2}{9}+\frac{b^2}{2}. Applicare la formula: x\left(a+b\right)=xa+xb, dove a=\frac{a}{3}, b=\frac{-b^2}{2}, x=\frac{a^2}{9} e a+b=\frac{a}{3}+\frac{-b^2}{2}. Applicare la formula: x\left(a+b\right)=xa+xb, dove a=\frac{a}{3}, b=\frac{-b^2}{2}, x=\frac{b^2}{2} e a+b=\frac{a}{3}+\frac{-b^2}{2}. Applicare la formula: \frac{a}{b}\frac{c}{f}=\frac{ac}{bf}, dove a=a^2, b=9, c=a, a/b=\frac{a^2}{9}, f=3, c/f=\frac{a}{3} e a/bc/f=\frac{a^2}{9}\frac{a}{3}.
((a^2)/9+(b^2)/2)(a/3+(-b^2)/2)
Risposta finale al problema
$\frac{a^{3}}{27}+\frac{-a^2b^2}{18}+\frac{b^2a}{6}+\frac{-b^{4}}{4}$