Simplify $\left(\sqrt[5]{9}\right)^{15}$ using the power of a power property: $\left(a^m\right)^n=a^{m\cdot n}$. In the expression, $m$ equals $\frac{1}{5}$ and $n$ equals $15$

Applicare la formula: $\frac{a}{b}c$$=\frac{ca}{b}$, dove $a=1$, $b=5$, $c=15$, $a/b=\frac{1}{5}$ e $ca/b=15\left(\frac{1}{5}\right)$

Applicare la formula: $\frac{a}{b}$$=\frac{a}{b}$, dove $a=15$, $b=5$ e $a/b=\frac{15}{5}$

Applicare la formula: $a^b$$=a^b$, dove $a=9$, $b=3$ e $a^b=9^{3}$