Applicare la formula: $ax=b$$\to \frac{ax}{a}=\frac{b}{a}$, dove $a=\sqrt{6}-\sqrt{2}$, $b=4$ e $x=\sqrt{a}+\sqrt{b}$

Applicare la formula: $\frac{a}{a}$$=1$, dove $a=\sqrt{6}-\sqrt{2}$ e $a/a=\frac{\left(\sqrt{6}-\sqrt{2}\right)\left(\sqrt{a}+\sqrt{b}\right)}{\sqrt{6}-\sqrt{2}}$

Applicare la formula: $x+a=b$$\to x=b-a$, dove $a=\sqrt{b}$, $b=\frac{4}{\sqrt{6}-\sqrt{2}}$, $x+a=b=\sqrt{a}+\sqrt{b}=\frac{4}{\sqrt{6}-\sqrt{2}}$, $x=\sqrt{a}$ e $x+a=\sqrt{a}+\sqrt{b}$

Applicare la formula: $x^a=b$$\to \left(x^a\right)^{inverse\left(a\right)}=b^{inverse\left(a\right)}$, dove $a=\frac{1}{2}$, $b=\frac{4}{\sqrt{6}-\sqrt{2}}-\sqrt{b}$, $x^a=b=\sqrt{a}=\frac{4}{\sqrt{6}-\sqrt{2}}-\sqrt{b}$, $x=a$ e $x^a=\sqrt{a}$

Applicare la formula: $\left(x^a\right)^b$$=x$, dove $a=\frac{1}{2}$, $b=2$, $x^a^b=\left(\sqrt{a}\right)^2$, $x=a$ e $x^a=\sqrt{a}$