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Apply the formula: $\frac{x}{a}$$=xinvfrac\left(a\right)$, where $a=\frac{21}{10}$, $x=\sqrt[3]{6x^2-x^3}+x$ and $x/a=\frac{\sqrt[3]{6x^2-x^3}+x}{2.1}$
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$\lim_{x\to\infty }\left(invfrac\left(2.1\right)\left(\sqrt[3]{6x^2-x^3}+x\right)\right)$
Learn how to solve calcolo differenziale problems step by step online. (x)->(infinity)lim(((6x^2-x^3)^(1/3)+x)/2.1). Apply the formula: \frac{x}{a}=xinvfrac\left(a\right), where a=\frac{21}{10}, x=\sqrt[3]{6x^2-x^3}+x and x/a=\frac{\sqrt[3]{6x^2-x^3}+x}{2.1}. Factor the polynomial 6x^2-x^3 by it's greatest common factor (GCF): x^2. Apply the formula: \left(ab\right)^n=a^nb^n. Simplify \sqrt[3]{x^2} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 2 and n equals \frac{1}{3}.
