Impara online a risolvere i problemi di passo dopo passo. (x)->(-infinito)lim(((8x^6+1)^(1/2))/(2x^3-x+2)). Applicare la formula: \lim_{x\to c}\left(\frac{a}{b}\right)=\lim_{x\to c}\left(\frac{\frac{a}{sign\left(c\right)fgrow\left(b\right)}}{\frac{b}{sign\left(c\right)fgrow\left(b\right)}}\right), dove a=\sqrt{8x^6+1}, b=2x^3-x+2, c=- \infty , a/b=\frac{\sqrt{8x^6+1}}{2x^3-x+2} e x->c=x\to{- \infty }. Applicare la formula: \lim_{x\to c}\left(\frac{a}{b}\right)=\lim_{x\to c}\left(\frac{radicalfrac\left(a\right)}{radicalfrac\left(b\right)}\right), dove a=\frac{\sqrt{8x^6+1}}{-x^3}, b=\frac{2x^3-x+2}{-x^3} e c=- \infty . Applicare la formula: \lim_{x\to c}\left(\frac{a}{b}\right)=\lim_{x\to c}\left(\frac{splitfrac\left(a\right)}{splitfrac\left(b\right)}\right), dove a=\sqrt{\frac{8x^6+1}{\left(-x^3\right)^{2}}}, b=\frac{2x^3-x+2}{-x^3} e c=- \infty . Applicare la formula: \frac{a}{a}=1, dove a/a=\frac{1}{2}.

(x)->(-infinito)lim(((8x^6+1)^(1/2))/(2x^3-x+2))