$\lim_{x\to0}\left(\left(e^x+x\right)^{\frac{1}{x}}\right)$

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Final answer to the problem

$e^{2}$
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Step-by-step Solution

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Apply the formula: $\lim_{x\to c}\left(a^b\right)$$=\lim_{x\to c}\left(e^{b\ln\left(a\right)}\right)$, where $a=e^x+x$, $b=\frac{1}{x}$ and $c=0$

$\lim_{x\to0}\left(e^{\frac{1}{x}\ln\left(e^x+x\right)}\right)$

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$\lim_{x\to0}\left(e^{\frac{1}{x}\ln\left(e^x+x\right)}\right)$

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Learn how to solve problems step by step online. (x)->(0)lim((e^x+x)^(1/x)). Apply the formula: \lim_{x\to c}\left(a^b\right)=\lim_{x\to c}\left(e^{b\ln\left(a\right)}\right), where a=e^x+x, b=\frac{1}{x} and c=0. Apply the formula: a\frac{b}{c}=\frac{ba}{c}, where a=\ln\left(e^x+x\right), b=1 and c=x. Apply the formula: \lim_{x\to c}\left(a^b\right)={\left(\lim_{x\to c}\left(a\right)\right)}^{\lim_{x\to c}\left(b\right)}, where a=e, b=\frac{\ln\left(e^x+x\right)}{x} and c=0. Apply the formula: \lim_{x\to c}\left(a\right)=a, where a=e and c=0.

Final answer to the problem

$e^{2}$

Exact Numeric Answer

$7.3890561$

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Function Plot

Plotting: $\left(e^x+x\right)^{\frac{1}{x}}$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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