Impara online a risolvere i problemi di passo dopo passo. ln(sec(y)/sin(x+1))=c. Applicare la formula: \ln\left(\frac{a}{b}\right)=\ln\left(a\right)-\ln\left(b\right), dove a=\sec\left(y\right) e b=\sin\left(x+1\right). Applicare la formula: x+a=b\to x=b-a, dove a=-\ln\left(\sin\left(x+1\right)\right), b=c, x+a=b=\ln\left(\sec\left(y\right)\right)-\ln\left(\sin\left(x+1\right)\right)=c, x=\ln\left(\sec\left(y\right)\right) e x+a=\ln\left(\sec\left(y\right)\right)-\ln\left(\sin\left(x+1\right)\right). Applicare la formula: \ln\left(a\right)=b\to e^{\ln\left(a\right)}=e^b, dove a=\sec\left(y\right) e b=c+\ln\left(\sin\left(x+1\right)\right). Applicare la formula: e^{\ln\left(x\right)}=x, dove x=\sec\left(y\right).

ln(sec(y)/sin(x+1))=c