Final answer to the problem
$y=\frac{62}{19}$
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1
Express the numbers in the equation as logarithms of base $10$
$\log \left(y+2\right)=\log \left(10^{1}\right)+\log \left(2y-6\right)$
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$\log \left(y+2\right)=\log \left(10^{1}\right)+\log \left(2y-6\right)$
Learn how to solve problems step by step online. log(y+2)=1+log(2*y+-6). Express the numbers in the equation as logarithms of base 10. Apply the formula: x^1=x, where x=10. Apply the formula: \log_{a}\left(x\right)+\log_{a}\left(y\right)=\log_{a}\left(xy\right), where a=10, x=10 and y=2y-6. Apply the formula: \log_{a}\left(x\right)=\log_{a}\left(y\right)\to x=y, where a=10, x=y+2 and y=10\left(2y-6\right).
Final answer to the problem
$y=\frac{62}{19}$
Exact Numeric Answer
$y=3.2631579$
