Impara online a risolvere i problemi di prodotti speciali passo dopo passo. log(3*x+12)-log(4*x+-10)=0. Applicare la formula: \log_{b}\left(x\right)-\log_{b}\left(y\right)=\log_{b}\left(\frac{x}{y}\right), dove b=10, x=3x+12 e y=4x-10. Applicare la formula: \log_{b}\left(x\right)=a\to \log_{b}\left(x\right)=\log_{b}\left(b^a\right), dove a=0, b=10, x=\frac{3x+12}{4x-10} e b,x=10,\frac{3x+12}{4x-10}. Applicare la formula: \log_{a}\left(x\right)=\log_{a}\left(y\right)\to x=y, dove a=10, x=\frac{3x+12}{4x-10} e y=1. Applicare la formula: \frac{a}{b}=c\to a=cb, dove a=3x+12, b=4x-10 e c=1.

log(3*x+12)-log(4*x+-10)=0