Final answer to the problem
$x=4$
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1
Express the numbers in the equation as logarithms of base $10$
$\log \left(x\right)+\log \left(x+21\right)=\log \left(10^{2}\right)$
Impara online a risolvere i problemi di passo dopo passo.
$\log \left(x\right)+\log \left(x+21\right)=\log \left(10^{2}\right)$
Impara online a risolvere i problemi di passo dopo passo. log(x)+log(x+21)=2. Express the numbers in the equation as logarithms of base 10. Apply the formula: \log_{a}\left(x\right)+\log_{a}\left(y\right)=\log_{a}\left(xy\right), where a=10 and y=x+21. Apply the formula: \log_{b}\left(b^a\right)=a, where a=2 and b=10. Apply the formula: x\left(a+b\right)=xa+xb, where a=x, b=21 and a+b=x+21.
Final answer to the problem
$x=4$
