$\log \left(x-1\right)+\log \left(x+1\right)=2\log \left(x+2\right)$

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$\log \left(x-1\right)+\log \left(x+1\right)=\log \left(\left(x+2\right)^2\right)$

Learn how to solve problems step by step online. log(x+-1)+log(x+1)=2log(x+2). Apply the formula: a\log_{b}\left(x\right)=\log_{b}\left(x^a\right), where a=2, b=10 and x=x+2. Apply the formula: \log_{a}\left(x\right)+\log_{a}\left(y\right)=\log_{a}\left(xy\right), where a=10, x=x-1 and y=x+1. Apply the formula: \left(a+b\right)\left(a+c\right)=a^2-b^2, where a=x, b=1, c=-1, a+c=x+1 and a+b=x-1. Apply the formula: \log_{a}\left(x\right)=\log_{a}\left(y\right)\to x=y, where a=10, x=x^2-1 and y=\left(x+2\right)^2.