Simplify $\sqrt[6]{25^3}$ using the power of a power property: $\left(a^m\right)^n=a^{m\cdot n}$. In the expression, $m$ equals $3$ and $n$ equals $\frac{1}{6}$

Applicare la formula: $\frac{a}{b}c$$=\frac{ca}{b}$, dove $a=1$, $b=6$, $c=3$, $a/b=\frac{1}{6}$ e $ca/b=3\cdot \left(\frac{1}{6}\right)$

Applicare la formula: $\frac{a}{b}$$=\frac{a}{b}$, dove $a=3$, $b=6$ e $a/b=\frac{3}{6}$

Applicare la formula: $x^a$$=pfgmin\left(x\right)^a$, dove $a=\frac{1}{2}$ e $x=25$

Applicare la formula: $\left(x^a\right)^b$$=x$, dove $a=2$, $b=1$, $x^a^b=\sqrt{5^{2}}$, $x=5$ e $x^a=5^{2}$