Esercizio
$\sqrt{\frac{4^{n+\frac{1}{2}}\left(\sqrt{2^{n-2}}\right)}{\sqrt{\frac{1}{2}\left(2^n\right)}}}$
Soluzione passo-passo
Impara online a risolvere i problemi di passo dopo passo. ((4^(n+1/2)2^(n-2)^(1/2))/((1/2*2^n)^(1/2)))^(1/2). Simplify \sqrt{2^{\left(n-2\right)}} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals n-2 and n equals \frac{1}{2}. Applicare la formula: \left(ab\right)^n=a^nb^n. Applicare la formula: \frac{a^m}{a^n}=a^{\left(m-n\right)}, dove a^n=2^{\frac{1}{2}n}, a^m=2^{\frac{1}{2}\left(n-2\right)}, a=2, a^m/a^n=\frac{4^{\left(n+\frac{1}{2}\right)}2^{\frac{1}{2}\left(n-2\right)}}{\frac{1}{\sqrt{2}}2^{\frac{1}{2}n}}, m=\frac{1}{2}\left(n-2\right) e n=\frac{1}{2}n. Applicare la formula: \frac{a}{\frac{b}{c}}=\frac{ac}{b}, dove a=4^{\left(n+\frac{1}{2}\right)}2^{\left(\frac{1}{2}\left(n-2\right)-\frac{1}{2}n\right)}, b=1, c=\sqrt{2}, a/b/c=\frac{4^{\left(n+\frac{1}{2}\right)}2^{\left(\frac{1}{2}\left(n-2\right)-\frac{1}{2}n\right)}}{\frac{1}{\sqrt{2}}} e b/c=\frac{1}{\sqrt{2}}.
((4^(n+1/2)2^(n-2)^(1/2))/((1/2*2^n)^(1/2)))^(1/2)
Risposta finale al problema
$\frac{4^{\left(\frac{1}{2}n+\frac{1}{4}\right)}}{\sqrt[4]{2}}$