Impara online a risolvere i problemi di passo dopo passo. 2sin(x)+(3cos(x))/(2sin(x)+3)-cos(x)=0. Applicare la formula: x+a=b\to x=b-a, dove a=\frac{3\cos\left(x\right)}{2\sin\left(x\right)+3}-\cos\left(x\right), b=0, x+a=b=2\sin\left(x\right)+\frac{3\cos\left(x\right)}{2\sin\left(x\right)+3}-\cos\left(x\right)=0, x=2\sin\left(x\right) e x+a=2\sin\left(x\right)+\frac{3\cos\left(x\right)}{2\sin\left(x\right)+3}-\cos\left(x\right). Applicare la formula: a+\frac{b}{c}=\frac{b+ac}{c}, dove a=-\cos\left(x\right), b=3\cos\left(x\right), c=2\sin\left(x\right)+3, a+b/c=\frac{3\cos\left(x\right)}{2\sin\left(x\right)+3}-\cos\left(x\right) e b/c=\frac{3\cos\left(x\right)}{2\sin\left(x\right)+3}. Applicare la formula: -\left(a+b\right)=-a-b, dove a=2\sin\left(x\right), b=3, -1.0=-1 e a+b=2\sin\left(x\right)+3. Applicare la formula: \frac{a}{b}=c\to a=cb, dove a=-\left(3\cos\left(x\right)+\left(-2\sin\left(x\right)-3\right)\cos\left(x\right)\right), b=2\sin\left(x\right)+3 e c=2\sin\left(x\right).

2sin(x)+(3cos(x))/(2sin(x)+3)-cos(x)=0