Impara online a risolvere i problemi di passo dopo passo. 3x+4=log(49^((2*x+-3)/(logn(10,7)))). Applicare la formula: \log_{b}\left(x^a\right)=a\log_{b}\left(x\right), dove a=\frac{2x-3}{\log \left(7\right)}, b=10 e x=49. Applicare la formula: a\frac{b}{c}=\frac{ba}{c}, dove a=\log \left(49\right), b=2x-3 e c=\log \left(7\right). Applicare la formula: \frac{\log_{b}\left(x\right)}{\log_{b}\left(a\right)}=\log_{a}\left(x\right), dove a=7, b=10 e x=49. Applicare la formula: \log_{a}\left(b\right)=logf\left(b,a\right), dove a=7, b=49 e a,b=7,49.

3x+4=log(49^((2*x+-3)/(logn(10,7))))