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Apply the formula: $a^x=b$$\to \log_{a}\left(a^x\right)=\log_{a}\left(b\right)$, where $a=4$, $b=\left(\frac{1}{64}\right)^{\left(5x+2\right)}$ and $x=x-10$
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$\log_{4}\left(4^{\left(x-10\right)}\right)=\log_{4}\left(\left(\frac{1}{64}\right)^{\left(5x+2\right)}\right)$
Learn how to solve problems step by step online. Solve the exponential equation 4^(x-10)=(1/64)^(5x+2). Apply the formula: a^x=b\to \log_{a}\left(a^x\right)=\log_{a}\left(b\right), where a=4, b=\left(\frac{1}{64}\right)^{\left(5x+2\right)} and x=x-10. Apply the formula: \log_{b}\left(b^a\right)=a, where a=x-10 and b=4. Apply the formula: x+a=b\to x+a-a=b-a, where a=-10, b=\log_{4}\left(\left(\frac{1}{64}\right)^{\left(5x+2\right)}\right), x+a=b=x-10=\log_{4}\left(\left(\frac{1}{64}\right)^{\left(5x+2\right)}\right) and x+a=x-10. Apply the formula: x+a+c=b+f\to x=b-a, where a=-10, b=\log_{4}\left(\left(\frac{1}{64}\right)^{\left(5x+2\right)}\right), c=10 and f=10.
