$\left(4^5\right)^2\left(4^3\right)$

$\frac{3-3\sin\left(x\right)-\cos x\left(3\cos\left(x\right)\right)}{2\cos\left(x\right)^2}$

$3-\left(x-5\right)^2$

$\left(+31\right)+\left(-51\right)-\left(-14\right)$

$\frac{d}{dx}x^3-y^2=xy$

$\sin\left(x\right)-y=0$

$\frac{dy}{dx}=x^2-\frac{2}{3}y$