Final answer to the problem
$x\leq \frac{5}{2}$
Got another answer? Verify it here!
Step-by-step Solution
How should I solve this problem?
- Scegliere un'opzione
- Prodotto di binomi con termine comune
- Metodo FOIL
- Sostituzione di Weierstrass
- Dimostrare dal LHS (lato sinistro)
- Load more...
Can't find a method? Tell us so we can add it.
1
Apply the formula: $x+a\leq b$$=x\leq b-a$, where $a=-25$, $b=0$ and $x=4x^2$
$4x^2\leq 0+25$
Learn how to solve disuguaglianze problems step by step online.
$4x^2\leq 0+25$
Learn how to solve disuguaglianze problems step by step online. Solve the inequality 4x^2-25<=0. Apply the formula: x+a\leq b=x\leq b-a, where a=-25, b=0 and x=4x^2. Apply the formula: a+b=a+b, where a=0, b=25 and a+b=0+25. Apply the formula: ax\leq b=x\leq \frac{b}{a}, where a=4, b=25 and x=x^2. Apply the formula: x^a\leq b=\left(x^a\right)^{\frac{1}{a}}\leq b^{\frac{1}{a}}, where a=2 and b=\frac{25}{4}.
Final answer to the problem
$x\leq \frac{5}{2}$
