$5\left(a+2\right)=\frac{40}{a}+\frac{2a}{3}$

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Final answer to the problem

$a=-\frac{15}{13}+\sqrt{2}i,\:a=-\frac{15}{13}-\sqrt{2}i$
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1

Apply the formula: $x\left(a+b\right)$$=xa+xb$, where $b=2$, $x=5$ and $a+b=a+2$

$5a+10=\frac{40}{a}+\frac{2a}{3}$

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$5a+10=\frac{40}{a}+\frac{2a}{3}$

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Learn how to solve problems step by step online. 5(a+2)=40/a+(2a)/3. Apply the formula: x\left(a+b\right)=xa+xb, where b=2, x=5 and a+b=a+2. Group the terms of the equation by moving the terms that have the variable a to the left side, and those that do not have it to the right side. Apply the formula: -\frac{b}{c}=\frac{expand\left(-b\right)}{c}, where b=40 and c=a. Apply the formula: -\frac{b}{c}=\frac{expand\left(-b\right)}{c}, where b=2a and c=3.

Final answer to the problem

$a=-\frac{15}{13}+\sqrt{2}i,\:a=-\frac{15}{13}-\sqrt{2}i$

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Function Plot

Plotting: $5\left(a+2\right)+\frac{-40}{a}+\frac{-2a}{3}$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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