Esercizio
$64^{2x+1}=8^{3x+5}$
Soluzione passo-passo
Impara online a risolvere i problemi di passo dopo passo. Solve the exponential equation 64^(2x+1)=8^(3x+5). Applicare la formula: x^b=pfgmin\left(x\right)^b, dove b=2x+1 e x=64. Simplify \left(2^{6}\right)^{\left(2x+1\right)} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 6 and n equals 2x+1. Applicare la formula: x^a=y^b\to x^a=pfgg\left(y,x\right)^b, dove a=6\left(2x+1\right), b=3x+5, x=2, y=8, x^a=2^{6\left(2x+1\right)}, x^a=y^b=2^{6\left(2x+1\right)}=8^{\left(3x+5\right)} e y^b=8^{\left(3x+5\right)}. Simplify \left(2^{3}\right)^{\left(3x+5\right)} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 3 and n equals 3x+5.
Solve the exponential equation 64^(2x+1)=8^(3x+5)
Risposta finale al problema
$x=3$