f(x)=(x^''-x+3)^3

 Esercizio

$f\left(x\right)=\left(x^{\left(2\right)}-x+3\right)^{\left(3\right)}$

 

Applicare la formula: $\left(a+b+c\right)^3$$=a^3+3a^2b+3a^2c+b^3+3ab^2+3b^2c+c^3+3ac^2+3bc^2+6abc$, dove $a=x^{''}$, $b=-x$ e $c=3$

$f\left(x\right)=x^{3''}-3x^{2''}x+9x^{2''}-x^3+3x^{''}x^2+9x^2+27+27x^{''}-27x-18x^{''}x$

 

Applicare la formula: $x^mx^n$$=x^{\left(m+n\right)}$, dove $m=''$ e $n=2$

$f\left(x\right)=x^{3''}-3x^{2''}x+9x^{2''}-x^3+3x^{\left(''+2\right)}+9x^2+27+27x^{''}-27x-18x^{''}x$

 

Applicare la formula: $x\cdot x^n$$=x^{\left(n+1\right)}$, dove $x^nx=-3x^{2''}x$, $x^n=x^{2''}$ e $n=2''$

$f\left(x\right)=x^{3''}-3x^{\left(2''+1\right)}+9x^{2''}-x^3+3x^{\left(''+2\right)}+9x^2+27+27x^{''}-27x-18x^{''}x$

 

Applicare la formula: $x\cdot x^n$$=x^{\left(n+1\right)}$, dove $x^nx=-18x^{''}x$, $x^n=x^{''}$ e $n=''$

$f\left(x\right)=x^{3''}-3x^{\left(2''+1\right)}+9x^{2''}-x^3+3x^{\left(''+2\right)}+9x^2+27+27x^{''}-27x-18x^{\left(''+1\right)}$

$f\left(x\right)=x^{3''}-3x^{\left(2''+1\right)}+9x^{2''}-x^3+3x^{\left(''+2\right)}+9x^2+27+27x^{''}-27x-18x^{\left(''+1\right)}$

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