Simplify $\left(\sqrt[4]{3x^4-8}\right)^7$ using the power of a power property: $\left(a^m\right)^n=a^{m\cdot n}$. In the expression, $m$ equals $\frac{1}{4}$ and $n$ equals $7$

Applicare la formula: $\frac{a}{b}c$$=\frac{ca}{b}$, dove $a=1$, $b=4$, $c=7$, $a/b=\frac{1}{4}$ e $ca/b=7\left(\frac{1}{4}\right)$