Final answer to the problem
$i\left(x\right)=x\left(x^2+3x-4\right)\left(x-2\right)$
Got another answer? Verify it here!
Step-by-step Solution
How should I solve this problem?
- Scegliere un'opzione
- Write in simplest form
- Semplificare
- Fattore
- Trovare le radici
- Load more...
Can't find a method? Tell us so we can add it.
1
Apply the formula: $\left(x+a\right)\left(x+b\right)$$=x^2+\left(a+b\right)x+ab$, where $a=-1$, $b=4$, $x+b=x+4$ and $x+a=x-1$
$i\left(x\right)=x\left(x^2+\left(-1+4\right)x-4\right)\left(x-2\right)$
2
Apply the formula: $a+b$$=a+b$, where $a=4$, $b=-1$ and $a+b=-1+4$
$i\left(x\right)=x\left(x^2+3x-4\right)\left(x-2\right)$
Final answer to the problem
$i\left(x\right)=x\left(x^2+3x-4\right)\left(x-2\right)$
