Esercizio
$m=\frac{\left(a+b\right)\left(a^3-b^3\right)}{a^2+ab+b^2}+b^2$
Soluzione passo-passo
Impara online a risolvere i problemi di passo dopo passo. m=((a+b)(a^3-b^3))/(a^2+abb^2)+b^2. Applicare la formula: a+b=\left(\sqrt[3]{a}+\sqrt[3]{\left|b\right|}\right)\left(\sqrt[3]{a^{2}}-\sqrt[3]{a}\sqrt[3]{\left|b\right|}+\sqrt[3]{\left|b\right|^{2}}\right), dove a=a^3 e b=-b^3. Simplify \sqrt[3]{a^3} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 3 and n equals \frac{1}{3}. Applicare la formula: \frac{a}{b}c=\frac{ca}{b}, dove a=1, b=3, c=3, a/b=\frac{1}{3} e ca/b=3\cdot \left(\frac{1}{3}\right). Applicare la formula: \frac{a}{b}=\frac{a}{b}, dove a=3, b=3 e a/b=\frac{3}{3}.
m=((a+b)(a^3-b^3))/(a^2+abb^2)+b^2
Risposta finale al problema
$m=\frac{\left(a+b\right)^2\left(a^{2}-ab+b^{2}\right)}{a^2+ab+b^2}+b^2$