Final answer to the problem
$x=-\frac{1}{2},\:x=\frac{1}{8}$
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1
Apply the formula: $x+a=b$$\to x=b-a$, where $a=-6x^{-1}-16$, $b=0$, $x+a=b=x^{-2}-6x^{-1}-16=0$, $x=x^{-2}$ and $x+a=x^{-2}-6x^{-1}-16$
$x^{-2}=-\left(-6x^{-1}-16\right)$
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$x^{-2}=-\left(-6x^{-1}-16\right)$
Learn how to solve problems step by step online. Solve the equation with radicals x^(-2)-6x^(-1)+-16=0. Apply the formula: x+a=b\to x=b-a, where a=-6x^{-1}-16, b=0, x+a=b=x^{-2}-6x^{-1}-16=0, x=x^{-2} and x+a=x^{-2}-6x^{-1}-16. Apply the formula: -\left(a+b\right)=-a-b, where a=-6x^{-1}, b=-16, -1.0=-1 and a+b=-6x^{-1}-16. Apply the formula: x^a=\frac{1}{x^{\left|a\right|}}. Move everything to the left hand side of the equation.
Final answer to the problem
$x=-\frac{1}{2},\:x=\frac{1}{8}$
