Final answer to the problem
$\left(x+5\right)^2-50$
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Step-by-step Solution
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- Prodotto di binomi con termine comune
- Metodo FOIL
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1
Apply the formula: $x^2+bx+c$$=x^2+bx+c+\left(\frac{b}{2}\right)^2-\left(\frac{b}{2}\right)^2$, where $b=10$ and $c=-25$
$x^2+10x-25+\left(\frac{10}{2}\right)^2- \left(\frac{10}{2}\right)^2$
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$x^2+10x-25+\left(\frac{10}{2}\right)^2- \left(\frac{10}{2}\right)^2$
Learn how to solve problems step by step online. x^2+10x+-25. Apply the formula: x^2+bx+c=x^2+bx+c+\left(\frac{b}{2}\right)^2-\left(\frac{b}{2}\right)^2, where b=10 and c=-25. Apply the formula: \frac{a}{b}=\frac{a}{b}, where a=10, b=2 and a/b=\frac{10}{2}. Apply the formula: \frac{a}{b}=\frac{a}{b}, where a=10, b=2 and a/b=\frac{10}{2}. Apply the formula: a^b=a^b, where a=5, b=2 and a^b=5^2.
Final answer to the problem
$\left(x+5\right)^2-50$
