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Apply the formula: $x^2+bx+c=0$$\to x=\frac{-b\pm \sqrt{b^2-4c}}{2}$, where $b=6$, $c=-10$, $bx=6x$, $x^2+bx=x^2+6x-10$ and $x^2+bx=0=x^2+6x-10=0$
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$x=\frac{-6\pm \sqrt{6^2-4\cdot -10}}{2}$
Learn how to solve equazioni quadratiche problems step by step online. Solve the quadratic equation x^2+6x+-10=0. Apply the formula: x^2+bx+c=0\to x=\frac{-b\pm \sqrt{b^2-4c}}{2}, where b=6, c=-10, bx=6x, x^2+bx=x^2+6x-10 and x^2+bx=0=x^2+6x-10=0. Apply the formula: a=b\to a=b, where a=x and b=\frac{-6\pm \sqrt{6^2-4\cdot -10}}{2}. Apply the formula: x=\frac{b\pm c}{f}\to x=\frac{b+c}{f},\:x=\frac{b-c}{f}, where b=-6, c=\sqrt{76} and f=2. Combining all solutions, the 2 solutions of the equation are.
