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$x^2+x+\frac{1}{4}$

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Solution

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Limit of this function

$\lim_{x\to0}\left(x^2+x+\frac{1}{4}\right)=\frac{1}{4}$
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Derivative of this function

$\frac{d}{dx}\left(x^2+x+\frac{1}{4}\right)=2x+1$
See step-by-step solution

Integral of this function

$\int\left(x^2+x+\frac{1}{4}\right)dx=\frac{x^{3}}{3}+\frac{1}{2}x^2+\frac{1}{4}x+C_0$
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